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one method as template, one normal -> don't work?

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mutable

Joined: 22 Jun 2010
Posts: 87

Posted: Mon Mar 14, 2011 11:36 am Post subject: one method as template, one normal -> don't work?

Hi, today i tried something like this

Code:

import std.stdio;

class Rect {
private short _x, _y;

this(in short x, in short y) {
   this._x = x;
   this._y = y;
}

void x(E)(in E x) {
   this._x = cast(short) x;
}

short x() const {
   return this._x;
}

short y() const {
   return this._y;
}

void y(E)(in E y) {
   this._y = cast(short) y;
}
}

void main() {
Rect r1 = new Rect(42, 23);
writefln("r1 %d:%d", r1.x(), r1.y());
r1.y(3.1456);
//writefln("r1 change %d:%d", r1.x, r1.y);
}

And i get this errors

Quote:

dmd -O "rect_tpl_teils.d" (im Verzeichnis: C:\Users\White\Desktop)
rect_tpl_teils.d(15): Error: function rect_tpl_teils.Rect.x conflicts with template rect_tpl_teils.Rect.x(E) at rect_tpl_teils.d(11)
rect_tpl_teils.d(23): Error: template rect_tpl_teils.Rect.y(E) conflicts with function rect_tpl_teils.Rect.y at rect_tpl_teils.d(19)
Kompilierung fehlgeschlagen.

After a lot of reading i fixed this "bug" (?)

Code:

import std.stdio;

class Rect {
private short _x, _y;

this(in short x, in short y) {
   this._x = x;
   this._y = y;
}

void x(E)(in E x) {
   this._x = cast(short) x;
}

short x(E = short)() const {
   return this._x;
}

short y(E = short)() const {
   return this._y;
}

void y(E)(in E y) {
   this._y = cast(short) y;
}
}

void main() {
Rect r1 = new Rect(42, 23);
writefln("r1 %d:%d", r1.x(), r1.y());
r1.y(3.1456);
//writefln("r1 change %d:%d", r1.x, r1.y);
}

I'm confused, should the compiler don't notice this itself?

Sorry for my bad english.

mutable

Joined: 22 Jun 2010
Posts: 87

Posted: Tue Mar 15, 2011 4:13 pm Post subject:

Most of the users here are not really active, isn't it? After a little researching, i found this The Topic can be closed (;

mutable

Joined: 22 Jun 2010
Posts: 87

Posted: Wed Mar 16, 2011 4:46 am Post subject:

(spammer) wrote:

mutable wrote:

Most of the users here are not really active, isn't it? Laughing

After a little researching, i found this

The Topic can be closed (;

They really helped me about my similar problem. Thanks for sharing this dude.

No problem.
Short time before i had found it, i have written an Article in german.
Maybe this article will help (or enjoy) you also. Smile

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