[JoeCoder]

I'm having trouble with typeof(). In the simplified example below, I want methodB initialize c as a new B() and not a new A(). typeof seems to return the type of whatever's pointing to the class and not the class itself. I could use classinfo.name, but I was wondering if there's an easier way. Here's my code:

[yossarian]

[csauls]

The thing with typeof() is that it doesn't read quite like you might expect it to. (It took me a while to learn this, as well.) It reads as "type of this expression, if it were to be evaluated," and not "type of this value/variable" as I'd originally thought. (The specs weren't so hot when it was first introduced.) Which means, a typeof() is evaluated by traversing the parse tree of its expression and determining what the type of its result would be. This type is then substituted in place for the typeof() expression itself, and parsing continues of the parent expression.

Whee!

So, as the previous poster said, the compiler doesn't have access to information such as underlying types of instances, because nothing in the typeof() expression is actually code-generated and executed. Its only typed.

(Which, incidentally, also means any function/method calls, or other such business appearing in a typeof() means absolutely nothing. The function is never called, the assignment never implemented, etc.)
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Chris Nicholson-Sauls